How to increase the resolving power of a tele | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The resolving power of an optical instrument is inversely proportional to the minimum angle of resolution. For a telescope,the resolving power is

Vedclass · Accepted Answer

By increasing the aperture of the objective lens for a telescope and the numerical aperture for a microscope.

Vedclass · Answer

(C) The resolving power of an optical instrument is inversely proportional to the minimum angle of resolution. For a telescope,the resolving power is given by $RP = \frac{D}{1.22 \lambda}$,where $D$ is the diameter of the objective lens and $\lambda$ is the wavelength of light. Thus,increasing the diameter $(D)$ increases the resolving power. For a microscope,the resolving power is given by $RP = \frac{2n \sin \beta}{1.22 \lambda}$,where $n \sin \beta$ is the numerical aperture. Thus,increasing the numerical aperture increases the resolving power. Therefore,increasing the aperture of the objective lens for a telescope and the numerical aperture for a microscope increases their respective resolving powers.

How to increase the resolving power of a telescope and a microscope?

Similar Questions

Two points separated by a distance of $0.1 \ mm$ can just be seen in a microscope when light of wavelength $6000 \ Å$ is used. If the light of wavelength $4800 \ Å$ is used,the limit of resolution will become: (in $mm$)

Assume that light of wavelength $600\, nm$ is coming from a star. The limit of resolution of a telescope whose objective has a diameter of $2\, m$ is $......... \times 10^{-7}\, rad$.

By increasing the aperture of the objective lens,how do the wavelength of light,the focal length of the objective lens,and the resolving power of an astronomical telescope change,respectively?

Wavelengths of light used in an optical instrument are $\lambda_1 = 4000 \; \mathring{A}$ and $\lambda_2 = 5000 \; \mathring{A}$. The ratio of their respective resolving powers (corresponding to $\lambda_1$ and $\lambda_2$) is:

The value of numerical aperture of the objective lens of a microscope is $1.25$. If light of wavelength $5000\,\mathring{A}$ is used, the minimum separation between two points, to be seen as distinct, will be....$\mu m$

Vedclass Test Series

Exam Paper Generator

Online Exam Module